算法代写 | CSE101: Design and Analysis of Algorithms
这个作业是完成二叉树相关的算法
 CSE101: Design and Analysis of Algorithms (CSE, UCSD, Spring-2020) Homework-05
 • The instructions are the same as in Homework-04.
 There are 5 questions for a total of 100 points.
 1. (15 points) Solve the following recurrence relations.
 (a) T(n) = 3T(n/3) + cn, T(1) = c
 (b) T(n) = 3T(n/3) + cn2
 , T(1) = c
 (c) T(n) = 3T(n − 1) + 1, T(1) = 1
 2. (20 points) Consider the following problem: You are given a pointer to the root r of a binary tree, where
 each vertex v has pointers v.lc and v.rc to the left and right child, and a value V al(v) > 0 . The value
 NIL represents a null pointer, showing that v has no child of that type. You wish to find the path from
 r to some leaf that maximizes the total values of vertices along that path. Give an algorithm to find the
 maximum sum of vertices along such a path along with a proof of correctneess and runtime analysis.
 3. (20 points) One ordered pair v = (v1, v2) dominates another ordered pair u = (u1, u2) if v1 ≥ u1 and
 v2 ≥ u2. Given a set S of ordered pairs, an ordered pair u ∈ S is called Pareto optimal for S if there
 is no v ∈ S such that v dominates u. Give an efficient algorithm that takes as input a list of n ordered
 pairs and outputs the subset of all Pareto-optimal pairs in S. Provide a proof of correctness along with
 the runtime analysis.
 4. (20 points) Given a list of distinct integers a[1…n], an inversion is a pair of elements a[i], a[j] such that
 a[i] > a[j] and i < j.
 Example: the list [41, 72, 3, 74, 31] has 5 inversions, namely (41, 3),(41, 31),(72, 3),(72, 31),(74, 31).
 Design a O(n log n) divide and conquer algorithm to count the number of inversions of a list of length n
 with distinct integers.
 (Hint: alter mergesort and keep count of the inversions during the merge part.) (No justification for
 correctness needed. Please give a justification of the runtime.)
 5. (25 points) An array A[1…n] is said to have a majority element if more than half of its entries are the
 same. Given an array, the task is to design an efficient algorithm to tell whether the array has a majority
 element, and, if so, to find that element. The elements of the array are not necessarily from some ordered
 domain like the integers, and so there can be no comparisons of the form “is A[i] ≥ A[j]?”. (Think of
 the array elements as GIF files, say.) However you can answer questions of the form: “is A[i] = A[j]?”
 in constant time.
 (a) Show how to solve this problem in O(nlogn) time. (Hint: Split the array A into two arrays A1 and
 A2 of half the size. Does knowing the majority elements of A1 and A2 help you figure out the majority
 element of A? If so, you can use a divide-and-conquer approach.) Provide a runtime analysis and proof
 of correctness.
 (b) Can you give a linear-time algorithm? (Hint: Here’s another divide-and-conquer approach:
 • Pair up the elements of A arbitrarily, to get n/2 pairs
 • Look at each pair: if the two elements are different, discard both of them; if they are the same, keep
 just one of them
 Show that after this procedure there are at most n/2 elements left, and that if A has a majority element
 then it’s a majority in the remaining set as well)
 1 of 1

 
                        